Question

Solve by substitution
y=6x-11
-2x-3y=-7

Answer 1

`y=6x-11\\ -2x-3y=-7\\\\\ substitute \ y=6x-11\ into\ equation\\\\\ -2x-3(6x-11)=-7\ \ \ \ |omit\ the\ bracket\\\\ -2x+18x+33=-7\\\\ 16x+33=-7 \ \ \ \ | subtract\ 33\\\\ 16x=-40\ \ \ | divide\ by\ 16\\\\ x=-(40)/(16)=-(5)/(2)\\\\ y=6x-11=6*(-(5)/(2))-11=-15-11=-26\\\\Solution:\\ \left \{ {{y=-26} \atop {x=-(5)/(2)}} \right.`

Answer 2

so you substitute y=6x-11 into -2x-3y=-7

-2x-3(6x-11)=-7
add like terms
-20x+33=-7
subtract 33 from both sides
-20x=-40
multiply by -1
20x=40
divide both sides by 20
x=2