Question

Find the vertex of the graph f(x)=-x^2+6x+1

Answer 1

Giving the function

`f(x)=x^2+6x+1`

the vertex is giving by

`h=(-b)/(2a)`

where

a=1

b=6

c=1

then

`h=(-6)/(2*1)`
`h=(-6)/(2)=-3`

then

`f(-3)=-3^2+6(-3)+1`
`f(-3)=9-18+1`
`f(-3)=-8`

then the vertex is in the point

(-3,-8)