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Hi, can you help me to solve this exercise please!

Hi, can you help me to solve this exercise please!-example-1
User Marisela
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1 Answer

23 votes
23 votes

Answer:

a. $25

b. $2025

Step-by-step explanation:

The profit the club makes is

profit = number of customers x amount charged per customer

Now, we are told that if we increase the price by $1, we will lose one customer.

Therefore, if we increase the price by $p then the number of customers we will have is

remaining customers = 70 customers - p = 70 - p

and the amount charged will become

amount charged per customer = 20 + p

Therefore, the profit will be

profit = ( 70 - p) ( 20 + p)

Now, the question is, for what value of p is the profit maximum?

Note that the equation for profit is a parabola (more precisely, a concave down parabola). Therefore, the vertex of the parabola gives the value of the maximum profit.

The parabola (70 - p)(20 + p) is graphed below.

As can be seen, the vertex of the parabola is at (25, 2025). This means that for p = 25, the profit is maximum.

In other words, if the club increases its price by $25, it will earn the maximum profit.

This maximum profit will be $2025.

Hence, to summarise.

a. $25

b. $2025

Hi, can you help me to solve this exercise please!-example-1
User Mohanraj
by
3.0k points