Jim must choose a number between 49 and 95 that is a multiple of 6, 9, and 18.

Kevin Hsiao asked Aug 24, 2023

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Kevin Hsiao asked Aug 24, 2023

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13 votes

6X < 95

9Y < 95

18Z < 95

Then

6X = 9Y

Then X = 9 , Y= 6

Number N= 9x6 = 54

54 also divide 18 , 54/18= 3

Then answer is Jim must choose N= 54

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