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Solve for the measure of angle ZCY in the regular hexagon .

Solve for the measure of angle ZCY in the regular hexagon .-example-1
User Ingo Kegel
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1 Answer

6 votes
6 votes

The diagram provided is a regular hexagon. This means that all the sides and angles are equal.

We can divide the hexagon into 6 parts by drawing diagonals as follows:

For a regular hexagon, all the labelled angles are equal, such that


a=b=c=d=e=f

The sum of all the angles is equal to 360°. Therefore, each angle will be equal to


\begin{gathered} a=(360)/(6) \\ a=60^(\circ) \end{gathered}

This means that angle ZCX is equal to 60°.

Hence, we can bring out Triangle XCZ from the question:

The base angles are equal since the vertical sides are equal.

Therefore,


\begin{gathered} 60+2\theta=180\text{ (Sum of angles in a triangle)} \\ 2\theta=180-60=120 \\ \therefore \\ \theta=60\degree \end{gathered}

From this, we can get the smaller triangle ZCY and find the angle ZCY as follows:

Therefore, angle ZCY can be calculated as


\begin{gathered} x+60+90=180\text{ (Sum of angles in a triangle)} \\ x=180-60-90 \\ x=30\degree \end{gathered}

Therefore, the value of angle ZCY is 30°.

Solve for the measure of angle ZCY in the regular hexagon .-example-1
Solve for the measure of angle ZCY in the regular hexagon .-example-2
Solve for the measure of angle ZCY in the regular hexagon .-example-3
User Zakiyah
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