Question

The lateral area of a frustum of a regular triangular pyramid is 1,081cm^2, and the altitude and lateral edges are 24cm and 26cm, respectively. Find the lengths of the sides of the bases.

Answer 1

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Answer 2

Lateral Area = 3 * ( a + b ) /2 * 24
1,081 = 36 * ( a + b ) /:36
a + b ≈ 30
(( a - b ) /2)² = 26 ² - 24² = 676 - 576 = 100
( a - b ) / 2 = 10
a - b = 20
a = b + 20
a + b = 30
2 b + 20 = 30
2 b = 10
b = 10 :2
b = 5 cm
a = 5 + 20
a = 25 cm