Question

the point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = (x – 12). what is the standard form of the equation for this line? x – 4y = 8 x – 4y = 2 4x – y = 8 4x – y = 2

Answer 1

Answer: The correct option is

(A)
`x-4y=8.`

Step-by-step explanation: Given that the point-slope form of the equation of the line passing through the points (-4, -3) and (12, 1) is given by

`y-1=(1)/(4)(x-12)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)`

We are to select the correct standard form of the equation for the above line.

From equation (i), we have

`y-1=(1)/(4)(x-12)\\\\\\\Rightarrow 4(y-1)=x-12\\\\\Rightarrow 4y-4=x-12\\\\\Rightarrow x-12-4y+4=0\\\\\Rightarrow x-4y-8=0\\\\\Rightarrow x-4y=8.`

Thus, the required standard form of the equation of the line is

`x-4y=8.`

Option (A) is CORRECT.

Answer 2

(y - 1) = 1/4(x - 12)
4(y - 1) = x - 12
4y - 4 = x - 12
x - 4y = -4 + 12
x - 4y = 8