72,467 views
26 votes
26 votes
How many grams of C2H2 are produced when water is added (in excess) to 5.00g CaC2CaC2+2H2O=C2H2+Ca(OH)2

User Sfletche
by
2.4k points

1 Answer

24 votes
24 votes

Step 1

The reaction must be completed and balanced:

CaC2 + 2H2O = C2H2 + Ca(OH)2

---------------

Step 2

Information provided:

H2O (water) is the excess.

CaC2 is the limiting reactant. This limits the production of C2H2

Information needed:

The molar mass of CaC2 (64.0 g/mol) and C2H2 (26.0 g/mol)

---------------

Step 3

By stoichiometry:

1 mol CaC2 = 64.0 g

1 molC2H2 = 26.0 g

64.0 g CaC2 -------- 26.0 g C2H2

5.00 g CaC2 -------- X

X = 5.00 g CaC2 x 26 g C2H2/64.0 g CaC2 = 2.03 g C2H2

Answer: 2.03 g C2H2

User Dviros
by
2.7k points