Question

A uniform disk of mass 2.01 kg has a radius of 0.100 m and spins with a frequency of 0.550 rev/s. What is its angular momentum? kg⋅m2/s

Answer 1

Given data

*The given mass of the uniform disk is m = 2.01 kg

*The given radius of the disk is r = 0.100 m

*The given frequency is

`\omega=0.550\text{ rev/ =(0.550 rev/s*}\frac{2\pi\text{ rad}}{1\text{ rev}})=3.45\text{ rad/s}`

The formula for the angular momentum is given as

`\begin{gathered} L=I\omega \\ =(1)/(2)mr^2*\omega \end{gathered}`

Substitute the known values in the above expression as

`\begin{gathered} L=(1)/(2)(2.01)(0.100)^2(3.45) \\ =0.034\text{ kg.m\textasciicircum{}2/s} \end{gathered}`