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How many moles of Ca are in 3.75 x 10^25 atoms of Ca?

1 Answer

13 votes

Answer:

62.3 mol Ca

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Atomic Structure

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

  • Using Dimensional Analysis

Step-by-step explanation:

Step 1: Define

3.75 × 10²⁵ atoms Ca

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

  1. Set up:
    \displaystyle 3.75 \cdot 10^(25) \ atoms \ Ca((1 \ mol \ Ca)/(6.022 \cdot 10^(23) \ atoms \ Ca))
  2. Multiply/Divide:
    \displaystyle 62.2717 \ mol \ Ca

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

62.2717 mol Ca ≈ 62.3 mol Ca

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