Question

A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 94 m long and 72 m wide. What is the length of a training track running around the field? (Use the value 3.14 for 1, and do not round your answer. Be sure to include the correct unit in your answer.)

Answer 1

Given data:

The given figure is shown.

The expresssion for the perimeter of the track is,

`\begin{gathered} P=(1)/(2)(\pi D)+2L+(1)/(2)(\pi D) \\ =\pi D+2L \end{gathered}`

Substitute the given values in the above expression.

`\begin{gathered} P=\pi(72\text{ m)+2(94 m)} \\ =226.08\text{ m +188 m} \\ =414.08\text{ m} \end{gathered}`

Thus, the perimeter of the track is 414.08 m.