Question

What is the volume of 0.23kg of pure water

Answer 1

m = 0,23kg = 230g
d = 1g/cm³

V = 230g / 1g/cm³ = 230cm³ = 0,23L

Answer 2

Answer: The volume of pure water is
`230cm^3`

Step-by-step explanation:

To calculate density of a substance, we use the equation:

`Density=(Mass)/(Volume)`

We are given:

Density of pure water =
`1g/cm^3`

Mass of pure water = 0.23kg = 230 g (Conversion factor: 1 kg = 1000 g)

Putting values in above equation, we get:

`1g/cm^3=\frac{230g}{\text{Volume of pure water}}\\\\\text{Volume of pure water}=230cm^3`

Hence, the volume of pure water is
`230cm^3`