Question

lynne walks dogs everyday to earn money. the fees she charges per month are 1 dog $40, 2 dogs $37.25, 3 dogs $34.50 each, 4 dogs $31.75 each. a pet store wants her to walk 8 dogs. if the pattern continues, how much will lynne charge to walk each of the 8 dogs?

Answer 1

1 dog = $40 2 dogs = $37.25 3 dogs = $34.50 4 dogs = $31.75 5 dogs = $29 6 dogs = $26.25 7 dogs = $23.50 8 dogs = $20.75 Pattern is minus $2.75

Answer 2

Answer: $20.75

Explanation:

Given : Lynne walks dogs everyday to earn money.

The fees she charges per month are 1 dog $40 each , 2 dogs $37.25 each, 3 dogs, $34.50 each and 4 dogs $31.75 each.

let x be the number of dogs and f(x) be fee she charged per month.

We know that, the rate of change of f(x), if pattern continues

`=(f(4)-f(1))/(4-1)=(\$31.75-\$40)/(4-1)=(-\$8.25)/(3)=-\$2.75`

Thus she decreases her fee $2.75 per on increment of number of dogs

For x=8 , to find f(8), we consider same pattern to 8 dogs.

Thus,

`(f(8)-f(1))/(8-1)=-\$2.75\\\Rightarrow(f(8)-40)/(7)=-2.75\\\Rightarrow\ f(8)-40=7*-2.75\\\Rightarrow\ f(8)-40=-19.25\\\Rightarrow\ f(8)=40-1925=\$20.75`