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Evaluate the function f(p) = p2 + 3p + 1 for p = -2

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p2 + 3p + 1
(-2)2 + 3(-2) +1
-4 +(-6) +1
-9
User Reallyethical
by
8.0k points
5 votes

Answer: -1

Explanation:

The given function :
f(p) = p^2 + 3p + 1

To find : The value of the given function (
f(p) = p^2 + 3p + 1) at p =-2.

We substitute the value of p=-2 in the given function, we get


f(-2) = (-2)^2 + 3(-2) + 1\\\\\Rightarrow\ f(-2)=4-6+1\\\\\Rightarrow\ f(-2)=-2+1\\\\\Rightarrow\ f(-2)=-1

Therefore , the value of the given function at p=-2 = -1

User LuisEspinoza
by
7.3k points

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