Final answer:
The mass of the material in the container after the reaction is complete is 39.92g.
Step-by-step explanation:
In the given reaction, 32g of sulfur reacts with 48g of oxygen to produce 80g of sulfur trioxide. This reaction allows us to determine the molar ratio of sulfur to oxygen to sulfur trioxide. Using this ratio, we can calculate the mass of sulfur trioxide produced when 16g of sulfur and 100g of oxygen react.
First, we calculate the molar amounts of sulfur and oxygen:
Sulfur: 16g / 32.07g/mol = 0.499 mol
Oxygen: 100g / 32g/mol = 3.125 mol
Next, we compare the mole ratio of sulfur to sulfur trioxide in the given reaction to find the limiting reactant:
1 mol Sulfur reacts with 1 mol Sulfur trioxide, so 0.499 mol Sulfur will produce 0.499 mol Sulfur trioxide
1 mol Oxygen reacts with 2 mol Sulfur trioxide, so 3.125 mol Oxygen will produce 1.5625 mol Sulfur trioxide
Since the mole ratio of Sulfur to Sulfur trioxide is 1:1, and the mole ratio of Oxygen to Sulfur trioxide is 2:1, the Oxygen is the limiting reactant. Therefore, only 0.499 mol of Sulfur trioxide can be produced.
To find the mass of Sulfur trioxide produced, we multiply the number of moles produced by the molar mass of Sulfur trioxide:
Mass of Sulfur trioxide = 0.499 mol × (80g/mol) = 39.92g
Therefore, the total mass of the material in the container after the reaction is complete is 39.92g.