Question

If a piece of metal adds 2090 Joules of heat to a glass of water that has a mass of 100 grams, how much will the temperature change? The specific heat of water is 4.18 J/g^ * K

Answer 1

A piece of metal adds 2090 Joules of heat to a glass of water.

The mass of the water is 100 grams.

How much will the temperature change?

The heat transferred from the metal to the glass of water is given by

`Q=m\cdot C\cdot\Delta T`

Where m is the mass, C is the specific heat of water (4.18 J/gK), Q is the amount of heat, and △T is the change in the temperature of the water.

Re-arranging the above equation for △T

`\begin{gathered} Q=m\cdot C\cdot\Delta T \\ \Delta T=(Q)/(m\cdot C) \end{gathered}`

Substitute the given values into the above equation

`\Delta T=(2090)/(100\cdot4.18)=5\; \degree C`

Therefore, the temperature change will be 5 °C

2nd option is the correct answer.