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Valeria · Answer 1 · 2023-02-01T08:41:22+0000

First, let's calculate the equivalent resistance between the two parallel resistances:

$\begin{gathered} (1)/(R_(eq))=(1)/(R_1)+(1)/(R_2)\\ \\ (1)/(R_(eq))=(1)/(12)+(1)/(44)\\ \\ (1)/(R_(eq))=(11)/(132)+(3)/(132)\\ \\ (1)/(R_(eq))=(14)/(132)=(7)/(66)\\ \\ R_(eq)=(66)/(7)\text{ \Omega} \end{gathered}$

(a)

To calculate the current in the circuit, let's use Ohm's Law with the equivalent resistance:

$\begin{gathered} I=(V)/(R)\\ \\ I=(17)/((66)/(7))\\ \\ I=1.803\text{ A} \end{gathered}$

(b)

To calculate the power, we can use the formula below:

$\begin{gathered} P=I\cdot V\\ \\ P=1.803\cdot17\\ \\ P=30.65\text{ W} \end{gathered}$

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