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PLEASEE HELP!!

How long would it take a ball to reach the ground if the height was modeled by
h(t) = -4t2 + 12t + 100, where t is the time in seconds?
A) about 6.7 seconds
B) about 7.6 seconds
C) about 3.7 seconds
D) about 5.2 seconds

User Jif
by
3.8k points

1 Answer

9 votes

Answer:

A)t=6.7

Explanation:

to understand this

you need to know about:

  • quadratic equation
  • quadratic equation word problems
  • solving quadratic

given:

h(t) = -4t² + 12t + 100

to solve:

t

tips and formulas:

  • the Ball will hit the ground when the height is 0
  • solving quadratics using quadratic formula
  • PEMDAS

let's solve:


step - 1 : \: define


- 4 {t}^(2) + 12t + 100 = 0


step - 2 : \\ divide \: both \: sides \: by \: - 4


{t}^(2) - 3t - 25 = 0


step - 3 : \\ solve \: the \: quadratic


formula : \\ x = \frac{ - b± \sqrt{ {b}^(2) - 4ac } }{2a}


define \: a ,b \: and \: c \\ which \: are \: 1, - 3 \: and \: - 25 \: respectively


t = \frac{ - ( - 3)± \sqrt{ {( - 3)}^(2) - 4.1. - 25 } }{2.1}


t = ( 3± √( 9 + 100) )/(2)


t = (3 + √( 109 ) )/(2)


t = (3 - √( 109 ) )/(2)


t = 6.7 \\ t = - 3.7


as \: we \: know \: time \: cannot \: be \: negative


\huge \therefore \: t = 6.7

User Kovyrin
by
2.9k points