Question

2. The surface area of a three-dimensional figure is the sum of the area measures for each of the

figure's faces. Find the surface area of the cube shown below.
3 in.
s=6e2
3 In
Part 1: How many faces does the cube shown above have? (1 point)
Part II: Find the area of one face of the cube shown above. Show your work. (2 points)
Part III: Find the surface area of the cube shown above. Show your work. (2 points)

Answer 1

Answer: 54

Explanation:

Answer 2

`\color{plum}\tt \: Answer \: \: part \: \: 1 :`

All cubes have six faces. Likewise, the cube shown above also has 6 faces.

`\color{plum}\tt \: Answer \: \: part \: \: 2 :`

Length of side of one face of cube = 3 inches

Area of one face :

= Side × Side

= 3 × 3

= 9 inch²

Therefore, the area of one face of this cube = 9 inch²

`\color{plum}\tt \: Answer \: \: part \: \: 3 :`

Area of cube = sum of the area of all faces

Then, the area of this cube :

`= 9 + 9 + 9 + 9 + 9 + 9`

`= 9 * 6`

`= 54 \: \: {inches}^(2)`

Therefore, the area of this cube = 54 inches²