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The radioactive isotope carbon-14 is present in small quantities in all life forms, and it is constantly replenished until the organism dies, after which it decays to stable carbon-12 at a rate proportional to the amount of carbon-14 present, with a half-life of 5556 years. Suppose C(t) is the amount of carbon-14 present at time t. The exponential decay differential equation that models this scenario is C'=-kC . Solve the differential equation to answer the following questions.

(a) Find the value of the constant k in the differential equation.

User Edxz
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As we know that the
k = ln(2)/t½
so putting values
= ln(2)/5556 years
=0.6931471/5556
=0.0001247565yr⁻
User Mavera
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