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2x/x2-25=10/x2-25 - 4/x+5
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2x/x2-25=10/x2-25 - 4/x+5

User AndyMac
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Hello,

x²-25≠0==>x≠5 and x≠-5


(2x)/(x^2-25)= (10)/(x^2-25)- (4)/(x+5) \\ (2x)/(x^2-25)= (10)/(x^2-25)- (4(x-5))/((x+5)(x-5)) \\ 2x=10-4x+20\\ 6x=30\\ x= 5
User Pmwood
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