Answer:
608g
Step-by-step explanation:
This is a combustion reaction between oxygen gas and C₆H₁₄.
The reaction expression is given as:
2C₆H₁₄ + 19O₂ → 12CO₂ + 14H₂O
We have been given 2 moles of C₆H₁₄
Let us find the number of moles of oxygen gas;
2 moles of C₆H₁₄ will react with 19 moles of O₂
Mass of oxygen gas reacting = number of moles x molar mass
molar mass of oxygen gas = 2(16) = 32g/mol
Mass of oxygen gas = 19 x 32 = 608g