Question

2) metal bar has a length of 3.0cm a width of 3.0cm and a height of 2.0 cm what is the volume of the water in liters would the bar displace.

Answer 1

Volume = 3.0 x 3.0 x 2.0 => 18.0 cm³

1 L ------------- 1000 cm³
? --------------- 18.0 cm³

Volume = 18 x 1 / 1000

Volume = 18 / 1000

V = 0.018 cm³

hope this helps!

Answer 2

0.0180 is the volume of the water in liters would the bar displace.

Step-by-step explanation:

The length metal bar = l = 3.0 cm

The width metal bar = w =3.0 cm

The height metal bar = h = 2.0 cm

Volume of the cuboid =
`l* w* h`

Volume of the metal bar = V

`V=l* w* h=3.0 cm* 3.0 cm* 2.0 cm=18.0 cm^3`

`1 cm^3= 1 mL`

`18.0 cm^3=18.0 mL`

1 mL = 0.001 L

`18.0 mL= 18.0 * 0.001 L=0.0180 L`

0.0180 is the volume of the water in liters would the bar displace.