Question

How do you rearrange the equation (2x) /(4pi) +((1-x) /2) =0 to solve for x?

Answer 1

`(2x)/(4 \pi ) + (1-x)/(2) =0 \\ (x)/(2 \pi ) + (1-x)/(2) = 0`
Then we will multiply both sides of the equation by 2 π :
x + π ( 1 - x ) = 0
x + π - π x = 0
x ( 1 - π ) = - π / · ( - 1 )
x ( π - 1 ) = π
x = π / ( π - 1 )