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Alamar · Answer 1 · 2017-11-27T12:05:58+0000

$(2x)/(4 \pi ) + (1-x)/(2) =0 \\ (x)/(2 \pi ) + (1-x)/(2) = 0$
Then we will multiply both sides of the equation by 2 π :
x + π ( 1 - x ) = 0
x + π - π x = 0
x ( 1 - π ) = - π / · ( - 1 )
x ( π - 1 ) = π
x = π / ( π - 1 )

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