What is the surface area of a square pyramid with base side lengths of 10 inches and a slant height of 14 inches

Question

asked Jan 14, 2017 113k views

1 Answer

Martin Wittemann · Answer 1 · 2017-01-20T21:14:57+0000

Answer:

The surface area is
$380\ in^(2)$

Explanation:

we know that

The surface area of the square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces

so

SA=b^(2)+4[(1)/(2)(b)(l)]

where

$b=10\ in$

$l=14\ in$ -----> the slant height

substitute the values

SA=10^(2)+4[(1)/(2)(10)(14)]

$SA=380\ in^(2)$