Question

what is the surface area of a square pyramid with base side lengths of 10 inches and a slant height of 14 inches

Answer 1

The surface area is
`380\ in^(2)`

Explanation:

we know that

The surface area of the square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces

so

`SA=b^(2)+4[(1)/(2)(b)(l)]`

where

`b=10\ in`

`l=14\ in` -----> the slant height

substitute the values

`SA=10^(2)+4[(1)/(2)(10)(14)]`

`SA=380\ in^(2)`