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The radius r of a sphere is increasing at a rate of 5 inches per minute.

The radius r of a sphere is increasing at a rate of 5 inches per minute.-example-1
User Igx
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1 Answer

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21 votes

Answer:


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Explanations:

The formula for calculating the volume of spheres is expressed as:


V=(4)/(3)\pi r^3

The rate of change of volume of the sphere is given as:


\begin{gathered} (dV)/(dt)=(dV)/(dr)\cdot(dr)/(dt) \\ (dV)/(dt)=4\pi r^2\cdot(dr)/(dt) \end{gathered}

a) Given the following parameters:


\begin{gathered} \text{radius }r\text{ =}8inches \\ (dr)/(dt)=5in\text{/min} \end{gathered}

Substitute into the result to have:


\begin{gathered} (dV)/(dt)=4\pi(8)^2\cdot5 \\ (dV)/(dt)=4\pi*64*5 \\ (dV)/(dt)=1280\pi in^3\text{/min} \end{gathered}

b) If the radius is 37inches, the rate of change of the volume is given as:


\begin{gathered} (dV)/(dt)=4\pi(37)^2\cdot5 \\ (dV)/(dt)=4\pi*1369*5 \\ (dV)/(dt)=27,380\pi in^3\text{/min} \end{gathered}

User Zorro
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