Question

Need help with problems 16 and 17, please? I'll do brainiac

the instructions say to write an equation for the graphs in slope-intercept form.

Answer 1

Answer: 16) y=-0.5x+3 and 17) y=2x-3

Explanation:

16: The slope-intercept form of a line is y=mx+b, where m is the slope, and b is the y-value at the y-intercept.

Since y=3 at x=0, the y-intercept is (0,3), and b=3.

Slope=
`(y_(2) -y_(1) )/(x_(2)-x_(1) )` where (
`x_(1) ,y_(1)`) and (
`x_(2) ,y_(2)`) are two points on the line. Choose (0,3) and (2,2):

Slope=
`(2-3)/(2-0)`=-0.5

Plug m=-0.5 and b=3 into y=mx+b:

y=-0.5x+3

17: The slope-intercept form of a line is y=mx+b, where m is the slope, and b is the y-value at the y-intercept.

Because y=-3 at x=0, the y-intercept is (0,-3), and b=-3.

Slope=
`(y_(2) -y_(1) )/(x_(2)-x_(1) )` where (
`x_(1) ,y_(1)`) and (
`x_(2) ,y_(2)`) are two points on the line. Choose (0,-3) and (1,-1):

Slope=
`(-3-(-1))/(0-1)`=
`(-2)/(-1)`=2

Plug m=2 and b=-3 into y=mx+b:

y=2x-3