F(x)=x^2+6x+8 What are the zeroes of the function? Write the smaller x first, and the larger x second

asked Jul 6, 2022 165k views

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6 votes

x²+6x+8= 0
Discriminant = 6²-4·1·8 = 4
Pythagorean theorem:
x = [-6±√(6²-4·1·8)]/[2· 1] = [-6±√4]/2 = -4, -2
Zeroes: -4,-2

Shlomi Fish answered Jul 7, 2022

6.3k points

8 votes

the answer is x6+6+6-7

PierU answered Jul 10, 2022

by PierU

5.9k points

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