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F(x)=x^2+6x+8 What are the zeroes of the function? Write the smaller x first, and the larger x second
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F(x)=x^2+6x+8 What are the zeroes of the function? Write the smaller x first, and the larger x second

User Bimzee
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2 Answers

6 votes
x²+6x+8= 0
Discriminant = 6²-4·1·8 = 4
Pythagorean theorem:
x = [-6±√(6²-4·1·8)]/[2· 1] = [-6±√4]/2 = -4, -2
Zeroes: -4,-2
User Shlomi Fish
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8.6k points
8 votes
the answer is x6+6+6-7
User PierU
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7.9k points
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