Question

A student throws a 0.22 kg rock horizontally at 20.0 m/s from 10.0 m above the ground. Find the initial kinetic energy of the rock.

Answer 1

44J

Step-by-step explanation:

Given parameters:

Mass of rock = 0.22kg

Initial velocity = 20m/s

Distance moved = 10m

Unknown:

Initial kinetic energy of the rock = ?

Solution:

To solve this problem, we need to understand that kinetic energy is the energy due to the motion of a body.

It is mathematically expressed as;

Kinetic energy =
`(1)/(2)` m v²

m is the mass

v is the velocity

Kinetic energy =
`(1)/(2)` x 0.22 x 20² = 44J