Question

A 1500 kg truck is acted upon by a force that decreases its speed from 25 m/s to 15 m/s in 8 s. What is the magnitude of the force acting on the truck?

Answer 1

Answer:

F = 1,875 N

Step-by-step explanation:

force=

`(change \: in \: momentum)/(time \: taken)`

∆H = m∆V

where ∆H ----> change in momentum.

( final momentum - initial momentum )

and ∆V ----> change in velocity

( final velocity - initial velocity )

and m ----> is mass

then f =

`(1500 * (25 - 15))/(8)`

= 1,875 N