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(√x+1/√x)^2find dy/ dx and substitute 2 in dy/ dx

(√x+1/√x)^2find dy/ dx and substitute 2 in dy/ dx
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(√x+1/√x)^2find dy/ dx and substitute 2 in dy/ dx

User Functor
by
8.2k points

1 Answer

3 votes
Hello,
That's better.

I suppose
y=( √(x) + (1)/( √(x) ) )^2 \\ y'=2*( √(x) + (1)/( √(x) ) )*( (1)/(2 √(x) ) - (3)/(2x √(x) ) )

If x=2 then

y'=2*( √(2) + (1)/( √(2) ) )*( (1)/(2 √(2) ) - (3)/(2*2* √(2) ) )\\ =2* (2+ √(2) )/( √(2) ) * (1)/(4*√(2) ) *(-1)\\ =- (2+ √(2) )/(4)

User Henry Crutcher
by
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