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4 votes
4(x+1)-ax=x+5 solve for x

User Vencaslac
by
8.3k points

2 Answers

3 votes

4(x+1)-ax=x+5


4x+4-ax=x+5
Expand


4x-ax=x+5-4
Subtract \ 4 \ from \ both \ sides


4x-ax=x+1


4x=x+1+ax
Add \ ax \ to \ both \ sides


4x-x=1+ax
Subtract \ x \ from \ both \ sides


3x=1+ax


3x-ax=1
Subtract \ ax \ from \ both \ sides


x(3-a)=1


x= (1)/(3-a)
User Ropali Munshi
by
8.4k points
6 votes
4(x + 1) - ax = x + 5
4(x) + 4(1) - ax = x + 5
4x + 4 - ax = x + 5
- x - x
3x + 4 - ax = 5
- 4 - 4
3x - ax = 1
x(3) - x(a) = 1
x(3 - a) = 1
3 - a 3 - a
x = 1/(3 - a)
User Sparklebeard
by
8.8k points

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