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The area of a rectangle is x2 - 2x - 15 and the length of the rectangle is x + 3. Find the width of the rectangle.

The area of a rectangle is x2 - 2x - 15 and the length of the rectangle is x + 3. Find-example-1
User Agoldis
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2 Answers

4 votes

Answer:

Width of the rectangle is (x-5)

Explanation:

We know that, the product of length and width gives the area of the rectangle.

The area of a rectangle is given as,


\Rightarrow \text{Area of rectangle}=\text{Length}* \text{Width}


\Rightarrow \text{Width}=\frac{\text{Area of rectangle}}{\text{Length}}

Factoring the area,


=x^2-2x-15


=x^2-5x+3x-15


=x(x-5)+3(x-5)


=(x+3)(x-5)

Putting it in the equation,


\Rightarrow \text{Width}=((x+3)(x-5))/((x+3))=(x-5)

User Kiminoa
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5 votes
Area of the rectangle= L* w

x^(2) -2x-15
On expanding;

x^(2) -5x+3x-15
=x(x-5)+3(x-5)
=(x+3)(x-5)
The width is (x-5)
User Splrs
by
7.9k points

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