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Given the function f(x) = 0.3(4)x, what is the value of f^(−1)(6)?

User CMont
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1 Answer

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f(x) = 0.3(4)x ------> f(x)=1.2x
As,
f(x)=y
So,
y=1.2x
re arranging x and y:
x=1.2y
y=1.2/x
f(-1)x= x/1.2
putting x=6:

f(-1) 6 = 6/1.2
f(-1) 6 = 5
User Paschalis
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