Please mark the questions right or wrong. if the answer is wrong, write the correct answer.

Bsky asked Apr 5, 2023

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Bsky asked Apr 5, 2023

by Bsky

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22 votes

Exponentials and square roots

We know that:

$\sqrt[n]{7}=7^{(1)/(n)}$

In this case, by convention:

$\sqrt[2]{7}=\sqrt[]{7}$

Then,

$\sqrt[]{7}=\sqrt[2]{7}=7^{(1)/(2)}$

Kastriot answered Apr 10, 2023

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