\footnotesize \displaystyle \bold {\int_{[0, (\pi)/(8) ] \cup[ (3 \pi)/(8), (\pi)/(2)]} \: (dx)/( √(1 - sin2x) ) }

asked Dec 5, 2023 160k views

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$\footnotesize \displaystyle \bold {\int_{[0, (\pi)/(8) ] \cup[ (3 \pi)/(8), (\pi)/(2)]} \: (dx)/( √(1 - sin2x) ) }$

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$\footnotesize \displaystyle \bold {\int_{[0, (\pi)/(8) ] \cup[ (3 \pi)/(8), (\pi)/(2)]} \: (dx)/( √(1 - sin2x) ) }$

$\footnotesize \displaystyle \bold {\int_{[0, (\pi)/(8) ] \cup[ (3 \pi)/(8), (\pi)/(2)]} \: (dx-example-1$

$\footnotesize \displaystyle \bold {\int_{[0, (\pi)/(8) ] \cup[ (3 \pi)/(8), (\pi)/(2)]} \: (dx-example-2$

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