Question

How many grams would 3.36 × 1023 molecules of copper (II) sulfate (CuSO4) weigh?

Answer 1

3.36 x 10^23 molecules x (1 mole/6.02 x 10^23 molecules) x (160 g/1 mole)
molar mass of a copper
3.36/6.02x160
copper sulphate cuso4weigh is 89.3g
this is the right equation
hope it helps

Answer 2

Answer: The mass of copper(II)sulfate are, 89.6 grams

Explanation: Given,

Molecules of
`CuSO_4` =
`3.36* 10^(23)`

Molar mass of
`CuSO_4` = 160 g/mole

First we have to calculate the moles of
`CuSO_4`.

As,
`6.022* 10^(23)` number of
`CuSO_4` atoms present in 1 mole of
`CuSO_4`

So,
`3.36* 10^(23)` number of
`CuSO_4` atoms present in
`(3.36* 10^(23))/(6.022* 10^(23))=0.56` mole of
`CuSO_4`

Now we have to calculate the mass of
`CuSO_4`

`\text{Mass of }CuSO_4=\text{Moles of }CuSO_4* \text{Molar mass of }CuSO_4`

`\text{Mass of }CuSO_4=(0.56mole)* (160g/mole)=89.6g`

Therefore, the mass of copper(II)sulfate are, 89.6 grams