Question

Write the half reactions for 2Li + H2 -> 2LiH.

Answer 1

The oxidation half-reaction is 2Li(s) -> 2Li+(aq) + 2e-, while the reduction half-reaction is H2(g) + 2e- -> 2H-(aq).

Step-by-step explanation:

The half reactions for the given equation are:

Oxidation: 2Li(s) -> 2Li+(aq) + 2e-

Reduction: H2(g) + 2e- -> 2H-(aq)

In the oxidation half-reaction, lithium (Li) is oxidized to lithium ions (Li+), while in the reduction half-reaction, hydrogen gas (H2) is reduced to hydrogen ions (H-).

Overall, the reaction is:

2Li(s) + H2(g) -> 2LiH(aq)

Answer 2

Li ----> Li+ + e-(oxidation)
now comes
Reduction:

H2 + 2e- ------> 2H
now by
Multiplying (1) by 2 and adding in (2) will give you the required equation..
..

2Li + H2 ---------> 2LiH
half reaction are either oxidation or reduction