Answer:
A
Explanation:
mean for producer A = (
155+156+158......)/10=155.9
Range = 163 -151 = 12
sample standard deviation = (√(£(x-mean)^2/(n-1))
mean for producer B=
(128+123+154+.....)/10 =155.9
range = 189-128 =61
sample standard deviation = (√(£(x-mean)^2/(n-1))
We can calculate that standard deviation of A is less than of B
So we can say A is more consistent and will likely be picked