Find the product of (3x − 7y)^2.

Question

asked Mar 8, 2017 226k views

2 Answers

Bclymer · Answer 1 · 2017-03-10T03:17:30+0000

(3x - 7y)^2 =
(3x - 7y)(3x - 7y) =
3x(3x - 7y) - 7y(3x - 7y) = 9x^2 - 21xy - 21xy + 49y^2...now combine like terms = 9x^2 - 42xy + 49y^2

Ashwin Hegde · Answer 2 · 2017-03-14T06:39:45+0000

Answer:

The product of given expression
$\left(3x-7y\right)^2$ is

Explanation:

Given : The expression
$\left(3x-7y\right)^2$

We have to find the product of the given expression
$\left(3x-7y\right)^2$

Apply perfect square formula ,
$\quad \left(a-b\right)^2=a^2-2ab+b^2$

we have a = 3x and b = 7y

we get,

$=\left(3x\right)^2-2\cdot \:3x\cdot \:7y+\left(7y\right)^2$

Simplify, we have,

=9x^2-42xy+49y^2

Thus, The product of given expression
$\left(3x-7y\right)^2$ is