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There are 5 red and 9 green balls in a bag. If you randomly choose balls one at a time, with replacement, what is the probability of choosing 2 red balls and then 1 green ball?

User Tempra
by
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2 Answers

6 votes

Answer:

The probability of choosing 2 red balls and then 1 green ball is:

225/2744

Explanation:

There are 5 red and 9 green balls in a bag.

Total balls=5+9=14

We randomly choose balls one at a time, with replacement.

(we draw a ball, look at it and place it in the bag and then draw another one)

P(choosing 2 red balls and then 1 green ball)

=
(5)/(14)* (5)/(14)* (9)/(14)

= 225/2744

Hence, the probability of choosing 2 red balls and then 1 green ball is:

225/2744

User Yanflea
by
7.8k points
2 votes
If there are 5 red & 9 green balls in one bag and you randomly choose the balls one at a time. The probability of choosing 2 red balls and then 1 green ball is 225/2744.
User Jouni
by
7.7k points

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