Question

Can't solve can u help

Answer 1

Given:

The equation of line p is

`y=-(1)/(3)x-3`

Line p and q are parallel.

To find:

The equation of line q.

Solution:

The slope intercept form of a line is

`y=mx+b`

Where, m is slope and b is y-intercept.

The equation of line p is

`y=-(1)/(3)x-3`

The slope of the line is
`-(1)/(3)`.

We know that the slopes of parallel lines are equal.

Line p and q are parallel. So,

Slope of line q =
`-(1)/(3)`

Line q passes through (6,-4) with slope
`-(1)/(3)`, so the equation of the line is

`(y-y_1)=m(x-x_1)`

Where, m is the slope.

`(y-(-4))=-(1)/(3)(x-6)`

`y+4=-(1)/(3)x+2`

`y=-(1)/(3)x+2-4`

`y=-(1)/(3)x-2`

Therefore, the equation of line q is
`y=-(1)/(3)x-2`.