Answer:
a. K₃PO₄ + 3 HCl ⇒ 3 KCl + H₃PO₄
b. C₂H₆ + 3.5 O₂ ⇒ 2 CO₂ + 3 H₂O
c. KClO₃ ⇒ KCl + 1.5 O₂
Step-by-step explanation:
a. Let's consider the following unbalanced equation. This is a double displacement reaction.
K₃PO₄ + HCl ⇒ KCl + H₃PO₄
We will begin balancing K atoms by multiplying KCl by 3.
K₃PO₄ + HCl ⇒ 3 KCl + H₃PO₄
Then, to balance Cl atoms, we multiply HCl by 3. This will be the balanced equation.
K₃PO₄ + 3 HCl ⇒ 3 KCl + H₃PO₄
b. Let's consider the following unbalanced equation. This is a combustion reaction.
C₂H₆ + O₂ ⇒ CO₂ + H₂O
First, we will balance C atoms by multiplying CO₂ by 2.
C₂H₆ + O₂ ⇒ 2 CO₂ + H₂O
Then, we balance H atoms by multiplying H₂O by 3.
C₂H₆ + O₂ ⇒ 2 CO₂ + 3 H₂O
Finally, we get the balanced equation multiplying O₂ by 3.5.
C₂H₆ + 3.5 O₂ ⇒ 2 CO₂ + 3 H₂O
c. Let's consider the following unbalanced equation. This is a decomposition reaction.
KClO₃ ⇒ KCl + O₂
Since K and Cl atoms are balanced, we will get the balanced equation multiplying O₂ by 1.5.
KClO₃ ⇒ KCl + 1.5 O₂