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The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y 7 = (x – 10). what is the standard form of the equation for this line?

The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y 7 = (x – 10). what is the standard form of the equation for this line?
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the point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y 7 = (x – 10). what is the standard form of the equation for this line?

User Hadi GhahremanNezhad
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1 Answer

6 votes

y+7=(x-10)\\\\y+7=x-10\\\\x-y-10-7=0\\\\\boxed{x-y-17=0}
User Wouter Bolsterlee
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