Question

In simplest radical form, what are the solutions to the quadratic equation 0 = –3x2 – 4x + 5

Answer 1

Answer: Answer is A if your doing edge nudity

Explanation:

Answer 2

`-3x^2-4x+5=0\\\\a=-3;\ b=-4;\ c=5\\\Delta=b^2-4ac\\\\\Delta=(-4)^2-4\cdot(-3)\cdot5=16+60=76 \ \textgreater \ 0\\\\therefore\\\sqrt\Delta=√(76)=√(4\cdot19)=\sqrt4\cdot√(19)=2√(19)\\x_1=(-b-\sqrt\Delta)/(2a)\ and\ x_2=(-b+\sqrt\Delta)/(2a)\\\\x_1=(4-2√(19))/(2\cdot(-3))=(4-2√(19))/(-6)=\boxed{-(2-√(19))/(3)}\\\\x_2=(4+2√(19))/(2\cdot(-3))=(4+2√(19))/(-6)=\boxed{-(2+√(19))/(3)}`