First, we assume the distribution is normal, since it is not given in the question.
Next, get a Z-table, such as
stat.ufl.edu/~athienit/Tables/Ztable.pdf
and look through the table for 97% shaded.
The corresponding Z-value should be 1.88 SD (standard deviations) for 96.99%.
Now since
Z=(X-mean)/SD
where
mean=500, SD=55
Solve for X.