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If 7.400 g of C6H6 is burned and the heat produced from the burning is added to 5691 g of water at 21 °C, what is the final temperature of the water?

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In your problems the possible solution is this one:

Ffr=μkFN=μkmg0.5(50000kg)(−9.8ms2)=−245000N a=F/m−245000N/50000kg=−4.9ms2t=v−v0a0−10ms−4.9ms2=2s

I hope you understand and satisfied with my answer
User Josoroma
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